True Discount – Aptitude Questions and Answers | Online True Discount MCQ Aptitude Test Quiz Name True Discount Category Online Aptitude Test Number of Questions 15 Time 30 Minutes Exam Type MCQ (Multiple Choice Questions) 1. A guy bought a cow for Rs. 3000 and sold it for Rs. 3600 the next day, giving the buyer…
True Discount – Aptitude Questions and Answers | Online True Discount MCQ Aptitude Test
Quiz Name
True Discount
Category
Online Aptitude Test
Number of Questions
15
Time
30 Minutes
Exam Type
MCQ (Multiple Choice Questions)
1. A guy bought a cow for Rs. 3000 and sold it for Rs. 3600 the next day, giving the buyer a two-year credit. If the rate of interest is 10% per year, the guy has made a profit of:
a. 0%
b. 5%
c. 7.5%
d. 10%
Answer: A
Explanation:
C.P. = 3000 rupees,S.P. = 3600 x 100/100 Plus (10 x 2) Equals 3000 rupees.Percentage gain = 0%.
2. The real discount on a Rs. 2562 payment due in four months is Rs. 122. The percentage rate is:
a. 12%
b. 13 1/3%
c. 15%
d. 14%
Answer: C
Explanation:
(2562 – 122) = Rs. 2440. P.W. = Rs. (2562 – 122) = Rs. 2440.S.I. for 4 months on Rs. 2440 is Rs. 122.15 percent rate = 100 × 122 / 2440 x ⅓.
3. A dealer owes a merchant Rs. 10,028 that is due in a year. After three months, the trader wishes to pay the account. How much cash should he pay if the interest rate is 12% per year?
a. Rs. 9025.20
b. Rs. 9200
c. Rs. 9600
d. Rs. 9560
Answer: B
Explanation:
P.W. of Rs. 10028 due in 9 months = Rs. 10028 x 100 /100 +12 x 9/12 = 9200 rupees
4. A man wishes to dispose of his scooter. There are two offers: one for Rs. 12,000 in cash and the other for Rs. 12,880 in credit to be paid after 8 months at an interest rate of 18 percent per year. Which one is the better deal?
a. Rs. 12,000 in cash
b. Rs. 12,880 at credit
c. Both are equally good
d.
Answer: A
Explanation:
Rs. 12880 x 100 /100 +18 x 8/12 = Rs. 12880 x 100 /100 +18 x 8/12 = Rs. 12880 = Rs. 12880 x 100 = Rs. 112= 11500 rupees
5. If a genuine discount of Rs. 10 is permitted on a bill of Rs. 110 due at the end of a period of time, the discount allowed on the same quantity due at the end of a period of time twice as long is:
a. Rs. 20
b. Rs. 21.81
c. Rs. 22
d. Rs. 18.33
Answer: D
Explanation:
For a period of time, S.I. on Rs. (110 – 10) Equals Rs. 10For double the period, S.I. on Rs. 100 Equals Rs. 20.Rs. 120 T.D. = Rs. (120 – 100) = Rs. 20T.D. on Rs. 110 = Rs. 20/120 x 110 = Rs. 18.33 T.D. on Rs. 110 = Rs. 20/120 x 110 = Rs. 18.33
6. Goods were purchased for Rs. 600 and sold for Rs. 688.50 on a 9-month credit, resulting in a 2 percent profit. The annual rate of interest is:
a. 16 2/3%
b. 14 1/2%
c. 13 1/3%
d. 15%
Answer: A
Explanation:
102 percent of Rs. 600 = 102 times 600 = Rs. 612,P.W. now equals Rs. 612, and total equals Rs. 688.50.T.D. = Rs. 76.50 (688.50 – 612) = Rs. 688.50S.I. on Rs. 612 for 9 months is thus Rs. 76.50.Rate = 100 x 76.50/ 612 x 3/4% = 16 %
7. At a rate of 16 percent per year, the real discount on a debt due in 9 months is Rs. 189. The bill’s total amount is:
a. Rs. 1386
b. Rs. 1764
c. Rs. 1575
d. Rs. 2268
Answer: B
Explanation:
P.W. will be Rs. x.Then pay S.I. on Rs. x for 9 months at a rate of 16 percent = Rs. 189.189 or x = 1575 = x x 16 x 9/12 x 1/100 = x x 16 x 9/12 x 1/100 = x x 16 x 9/12 x 1/100 =P.W. is equal to Rs. 1575.P.W. + T.D. equals Rs. (1575 + 189) = Rs. 1764.
8. A guy purchases a watch for Rs. 1950 in cash and sells it for Rs. 2200 on a one-year credit. If the interest rate is ten percent per year, the man:
a. gains Rs. 55
b. gains Rs. 50
c. loses Rs. 30
d. gains Rs. 30
Answer: B
Explanation:
S.P. = Rs. 2200 x 100/ 100 + S.P. = Rs. 2200 x 100/ 100 + S.P. = Rs. 2200 x 100/ 100 + S.P. = (10 x 1)= 2000 rupee,Gain = (2000 – 1950) x 50 = Rs.50
9. At a rate of 12% per year, the real discount on Rs. 1760 payable after a given period of time is Rs. 160. It is due at the following time:
a. 6 months
b. 8 months
c. 9 months
d. 10 months
Answer: D
Explanation:
P.W. = Rs. 1600 (1760 – 160).At a rate of 12%, S.I. on Rs. 1600 is Rs. 160.Time = 100 x 160/1600 x 12 = 5/6 years = 5/6 x 12 months = 10 months Time = 100 x 160/1600 x 12 = 5/6 years = 5/6 x 12 months = 10 months
10. The current value of Rs. 2310, which is due in two years and has a 15% annual interest rate, is:
a. Rs. 1750
b. Rs. 1680
c. Rs. 1840
d. Rs. 1443.75
11. The real reduction on the Rs. 260 owing after a specific period of time is Rs. 20. What will be the real discount on the same amount due in half the time, with the same rate of interest?
a. Rs. 10
b. Rs. 10.40
c. Rs. 15.20
d. Rs. 13
Answer: B
Explanation:
For a certain period of time, S.I. on Rs. (260 – 20) = Rs. 20.For half the period, S.I. on Rs. 240 Equals Rs. 10.T.D. on a sum of Rs. 250 equals Rs. 10.Rs. 260 T.D. = Rs. 10/250 x 260 = Rs. 10.40.
12.The real discount on Rs. 960 payable in 2 years is the same as the interest on Rs. 750 for 2 years. If the interest rate is the same in both situations, the answer is:
a. 12%
b. 14%
c. 15%
d. 16 2/3 %
Answer: B
Explanation:
S.I. on 750 rupees Equals T.D. on 960 rupees.This indicates that a P.W. of Rs. 960 payable in two years will cost Rs. 750.T.D. = (960 – 750) = 210 rupees
S.I. on Rs. 750 for two years is therefore Rs. 210.The rate is equal to 100 × 210/750 x 2% = 14%.
13. For a given time and rate, the simple interest and actual discount on a given sum are Rs. 85 and Rs. 80, respectively. The total is:
a. Rs. 1800
b. Rs. 1450
c. Rs. 1360
d. Rs. 6800
Answer: C
Explanation:
S.I. x T.D./(S.I.) – (T.D.) = 85 x 80/(85 – 80) = Rs. 1360.
14. The present value of Rs. 1404 payable in two equal half-yearly instalments at an annual simple interest rate of 8% is:
a. Rs. 1325
b. Rs. 1300
c. Rs. 1350
d. Rs. 1500
Answer: A
Explanation:
Required sum = Rs. 100 x 702/100 + (8 x 1)+100 x 702/ 100 100 x 702/ 100 + (8 x 1),675 + 650 = Rs. 1325 = 100 + 8 times.
15. If the real discount on a payment due in two years is Rs. 168 at a rate of 14 percent each year, the amount due is:
a. Rs. 768
b. Rs. 968
c. Rs. 1960
d. Rs. 2400
Answer: A
Explanation:
P.W. = 100 x T.D./R x T = 100 x 168/14 x 2 = 600 P.W. = 100 x T.D./R x T = 100 x 168/14 x 2 = 600 P.W.(600 + 168) = Rs. 768 Sum = (P.W. + T.D.).
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