Mixture & Alligation – Aptitude Questions and Answers | Online Mixture & Alligation MCQ Aptitude Test
Mixture and Alligation – Aptitude Questions and Answers | Online Mixture and Alligation MCQ Aptitude Test Quiz Name Mixture and Alligation Category Online Aptitude Test Number of Questions 15 Time 30 Minutes Exam Type MCQ (Multiple Choice Questions) 1. Fill a jar halfway with liquid, 3 parts water and 5 parts syrup. How much of the... explore below more
Mixture and Alligation – Aptitude Questions and Answers | Online Mixture and Alligation MCQ Aptitude Test
Quiz Name
Mixture and Alligation
Category
Online Aptitude Test
Number of Questions
15
Time
30 Minutes
Exam Type
MCQ (Multiple Choice Questions)
1. Fill a jar halfway with liquid, 3 parts water and 5 parts syrup. How much of the combination should be drained and replaced with water such that the mixture is half syrup and half water? a. 1/3 b. 1/4 c. 1/5 d. 1/7
Answer: C
Explanation: Assume the vessel is originally filled with 8 litres of liquid.Allow for the replacement of x litres of this liquid with water.Water quantity in new mixture = 3 – 3x/8 + x litres,Syrup quantity in new mixture = 5 – 5x/8 litres,3 – 3x/8 + x = 5 – 5×40 – 5x = 5x + 24,10 x 16 =x = 8/5 x = 8/5 x = 8/5 x = 8/5,As a result, a portion of the mixture was changed = 8/5 x 1/8 = 1/5.
2. Tea worth Rs. 126 per kg and Rs. 135 per kg are blended in a 1:1:2 ratio with a third type. If the combination costs Rs. 153 per kg, the third variety’s price per kilogramme will be: a. Rs. 169.50 b. Rs. 170 c. Rs. 175.50 d. Rs. 180
Answer: C
Explanation: Because the first and second variety are combined in equal amounts. As a result, their average cost is Rs. 126 + 135 = Rs. 130.50 2. So, the mixture is made by combining two kinds, one priced at Rs. 130.50 per kg and the other at, say, Rs. x per kg, at a ratio of 2:2, or 1:1. We need to figure out what x is. x – 153/22.50 = 1 x – 153 = 22.50 x = 175.5
3. A container holds a combination of two liquids A and B in a 7:5 ratio. The ratio of A and B becomes 7:9 when 9 litres of mixture are taken out and the can is filled with B. How many litres of liquid A did the can originally hold? a. 10 b. 20 c. 21 d. 25
Answer: C
Explanation: Assume the can contains 7x and 5x of mixes A and B at the start.7x – 7/12 x 9 litres = 7x – 21/4 litres Quantity of A in mixture left = 7x – 7/12 x 9 litres.Quantity of B remaining in the combination = 5x – 5/12 x 9 litres = 5x – 15/4 litre=7x – 21/4 /5x -15 + 9 = 7/9 = 28x – 21/20x + 21 = 7/9 = 252x – 189 = 140x + 147 = 112x = 336 = x = 3.As a result, the container held 21 litres of A.
4. A milk dealer has two milk cans. The first is made up of 25% water and 75% milk. The second is made up of 50% water. How much milk should he combine from each of the containers to make 12 litres of milk with a 3:5 water-to-milk ratio? a. 4 litres, 8 litres b. 6 litres, 6 litres c. 5 litres, 7 litres d. 7 litres, 5 litres
Answer: B
Explanation: Let’s say the price of a litre of milk is 1 milk in 1 litre mix = 3/4 litre in 1st can, C.P. of 1 litre mix in 1st can Re.3/4 Milk in 1 litre mix. in 2nd can = 1/2 litre, C.P. of 1 litre mix. in 2nd can = 1/2 litre, C.P. of 1 litre mix. in 2nd can = 1/2 litre, C.P. of 1 litre mix. in 2nd can = 1/2 1/2 litre milk in 1 litre final mix = 5/8 litre Re. 5/8 is the average price.As a result of the alligation rule, we have:1/8 : 1/8 Equals 1 : 1 ratio of two mixes,As a result, the amount of mixture extracted from each can is 1/2 x 12 = 6 litres.
5. How could a grocer combine two types of pulses that cost Rs. 15 and Rs. 20 per kg to get a combination worth Rs. 16.50 kg? a. 3 : 7 b. 5 : 7 c. 7 : 3 d. 7 : 5
Answer: C
Explanation: 3.50 : 1.50 = 7 : 3 is the required rate.
6. A dishonest milkman claims to sell his milk at cost, but he inflates the price by 25% by mixing it with water. The water content of the combination is: a. 4% b. 6% c. 20% d. 25%
Answer: C
Explanation: Let Re. 1 be the C.P. of 1 litre milk.Then, for 1 litre of combination, S.P. = Re. 1, Gain = 25%.1 litre mixture C.P. = Re. 100/125 x 1 = ⅘,As a result of the alligation rule, we have:Milk to water ratio = 4/5 : 1/5 = 4 : 1.As a result, the percentage of water in the combination is 1/5 x 100% = 20%.
7. How many kilogrammes of Rs. 9 per kg sugar must be combined with 27 kilogrammes of Rs. 7 per kg sugar in order to make a 10% profit by selling the combination at Rs. 9.24 per kg? a. 36 kg b. 42 kg c. 54 kg d. 63 kg
Answer: D
Explanation: S.P. for 1 kilogramme of mixture = Rs. 9.24, with a 10% gain.1 kilogramme of mixture C.P. = Rs. 100 x 9.24 = Rs. 8.40 110,As a result of the allilation rule, we have:The ratio of first- and second-kind quantities is 14:6 = 7:3.Allow x kg of first-class sugar to be combined with 27 kg of second-class sugar.7 : 3 = x : 27 is the result.63 kg = x = 7 x 27/3
8. There are 40 litres of milk in a container. 4 litres of milk were removed from this container and replaced with water. This procedure was done two more times. How much milk does the container currently hold? a. 26.34 litres b. 27.36 litres c. 28 litres d. 29.16 litres
Answer: D
Explanation: After three procedures, the amount of milk remaining is 40 1 – 4/40 TO THE POWER OF 3 litres.= 40 x 9/10 x 9/10 x 9/10 x 9/10 = 29.16 litres.
9. The alcohol content of a jar of whiskey is 40%. A portion of this whiskey was substituted with another that had 19 percent alcohol, resulting in a proportion of alcohol of 26 percent. The amount of whiskey that has been replaced is: a. 1/3 b. 2/3 c. 2/5 d. 3/5
Answer: B
Explanation: As a result of the alligation rule, we have,As a result, the ratio of the first and second values is 7:14 = 1:2.2/3 of the required quantity must be refilled.
10. In order to gain 16 percent on selling the combination at cost price, how much water must be combined with milk? a. 1 : 6 b. 6 : 1 c. 2 : 3 d. 4 : 3
Answer: A
Explanation: Let Re. 1 be the C.P. of a litre of milk.Gain = 50/3 percent, S.P. of 1 litre of mixture = Re.1.1 litre of combination C.P. = 100 x 3/350 x 1/7 = 6,We may calculate the ratio of water and milk using the law of alligation: 1/7 : 6/7 = 1 : 6.
11. Calculate the ratio of rice at Rs. 7.20 per kg to rice at Rs. 5.70 per kg to make a combination worth Rs. 6.30 per kg. a. 1 : 3 b. 2 : 3 c. 3 : 4 d. 4 : 5
Answer: B
Explanation: According to the alligation rule, the required ratio is 60:90 = 2:3.
12. In what ratio should a grocer blend two types of tea worth Rs. 60 per kg and Rs. 65 per kg so that he may profit 10% by selling the combination for Rs. 68.20 per kg? a. 3 : 2 b. 3 : 4 c. 3 : 5 d. 4 : 5
Answer: A
Explanation: 1 kilogramme of the mixture’s S.P. is Rs. 68.20, with a gain of 10%.1 kilogramme of the mixture’s C.P. = Rs. 100 /110x 68.20 = Rs. 62.According to the alligation rule, the required ratio is 3:2.
13. Type 1 rice costs Rs. 15 per kg, whereas Type 2 rice costs Rs. 20 per kg. When Type 1 and Type 2 rice are combined in a 2:3 ratio, the price per kilogramme of the mixed rice type is: a. Rs. 18 b. Rs. 18.50 c. Rs. 19 d. Rs. 19.50
Answer: A
Explanation: Let’s say the mixed variety’s pricing is Rs. x per kilogramme.We have (20 – x)/(x – 15) = 2/3 by the law of alligation.2x – 30 = 60 – 3x,5 times 90,x equals 18.
14. A total of 14.8 litres of wine is taken from a barrel and then filled with water. This procedure is repeated three times more. The amount of wine left in barrel to the amount of water in the cask is 16:65. What was the initial capacity of the cask? a. 18 litres b. 24 litres c. 32 litres d. 42 litres
Answer: B
Explanation: Then, after four processes, the quantity of wine remaining in the barrel Equals x 1 – 8/x TO THE POWER 4 litres,x(1 – (8/x) x(1 – (8/x) x(1 – (8/x 16/81 TO THE POWER OF 4/x,2/3 TO THE POWER 4 = 1 – 8/x TO THE POWER 4=x – 8 /x = 2/x = ⅔,2x = 3x – 24=24 = x.
15. A merchant owns 1000 kg of sugar, of which he sells a portion for 8% profit and the remainder for 18% profit. On the overall, he improves by 14%. The quantity sold at a profit of 18 percent is: a. 400 kg b. 560 kg c. 600 kg d. 640 kg
Answer: C
Explanation: According to the law of alligation, the ratio between the first and second portions is 4:6 = 2:3.,2nd type quantity = 3/5 x 1000 kg = 600 kg.
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