Infosys Aptitude Questions and Answers with Explanation: We’ve included Infosys Aptitude Questions and Answers with explanations in this article. Candidates can obtain sample Infosys Aptitude Questions and Answers by visiting this link. Job seekers can gauge the test’s difficulty level and save time while taking the online exam by studying these questions.
Please keep in mind that the Infosys Aptitude Questions and Answers For Freshers offered are Infosys sample questions and not actual questions. Students can better manage their time throughout the exam by memorizing these Infosys Aptitude Questions and Answers.
Contents
Infosys Aptitude Questions and Answers with Explanation 2025
- Number of Questions: 10
- Time Duration: 25 mins.
Topics
- Ratio and Proportion
- Boats and Streams
- Simple Interest
- Averages
- Partnership
- Problems on Boats and Streams
- Profits & Loss
- Percentages
- Compound Interest
- Volumes
- Probability
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Question and Answers On Infosys Aptitude
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Explanatory Samples of Infosys Aptitude Questions and Answers
1. A shop dealer makes his goods 25% above CP and then while selling gives a discount of 12% on MP. Find his profit %?
A. 15%
B. 12%
C. 11%
D. 10%
Answer – D. 10%
Explanation:
Let Cost Price (CP) = 100
Market Price (MP) = 125
Profit = 125*88/100 = 110
110 – 100 = 10%.
2. The average age of 30 boys in a class is equal to 14 years. When the age of the class teacher is included the average becomes 15 years. Find the age of the class teacher?
A. 45
B. 42
C. 50
D. 44
Answer – A. 45
Explanation:
Given that
Total ages of 30 boys = 14 x 30 = 420 years
Total age when class teacher is included = 15 x 31 = 465 years
Age of class teacher = 465 – 420 = 45 years
Hence, the age of the class teacher is 45 years.
3. The average of 11 numbers is 10.9. If the average of the first six is 10.5 and that of the last six is 11.4 the sixth number is?
A. 11.4
B. 11.5
C. 11.0
D. 11.3
Answer – B. 11.5
Explanation:
Given, 1 to 11 = 11 * 10.9 = 119.9
1 to 6 = 6 * 10.5 = 63
6 to 11 = 6 * 11.4 = 68.4
63 + 68.4 = 131.4 – 119.9 = 11.5
Therefore, 6th number = 11.5
4. If P can do a work in 6 days and Q can do the same work in 8 days. If R who can do the same work in 12 days, joins them, then the work will be completed in how many days?
A. 7/3 days
B. 8/3 days
C. 10/3 days
D. 11/3 days
Answer – B. 8/3 days
Explanation:
1/6 + 1/8 + 1/12 = 1/d.
D = 8/3 days
Therefore, the work will be completed in 8/3 days.
5. A and B rent a pasture for 10 months. A put in 80 cows for 7 months. How many can B put in for the remaining 3 months, if he pays half as much again as A?
A. 120
B. 280
C. 180
D. 200
Answer – B. 280
Explanation:
According to the given data
80* 7: x* 3 = 1:1 1/2
560: 3x = 2: 3
x = 280
6. Rama Krishna can finish a work in 20 days and Suresh in 25 days. They both work together for 5 days and then Suresh goes away. In how many days will Rama Krishna complete the remaining work?
A. 10 days
B. 11 days
C. 8 days
D. 9 days
Answer – B. 11 days
Explanation:
Let’s assume the completion of remaining work by Ramesh is x then, according to the given information
(5 + x)/20 + 5/25 = 1 => x = 11 days
7. How much water must be added to a bucket which contains 40 liters of milk at the cost price of Rs.3.50 per liter so that the cost of milk reduces to Rs.2 per liter?
A. 25 liters
B. 28 litres
C. 30 liters
D. 35 liters
Answer – C. 30 liters
Explanation:
Total cost price =Rs(40 x 7/2) = Rs.140
Cost per litre =Rs.2
Total quantity = 140/2 = 70 liters.
Water to be added =(70-40) =30 liters.
8. A man spends 60% of his income. His income is increased by 20% and his expenditure also increases by 10%. Find the percentage decrease in his saving?
A. 15%
B. 20%
C. 25%
D. 10%
Answer – D. 10%
Explanation:
Let us assume initially income is 100.
So, expenditure = 60 and saving = 40
Now income is increased by 20% that is 120.
So, expenditure = (70/100)*120 = 84 and saving = 36
so % percent decrease in saving = (4/40)*100 = 10%
9. 5 men and 10 boys can do a piece of work in 30 days and 8 men and 12 boys can do the work in 20 days then the ratio of daily work done by a man to that of the boy.
A. 6:1
B. 7:3
C. 4:5
D. 5:1
Answer – A. 6:1
Explanation:
5m + 10b = 1/30 and 8m + 12b = 1/20
after solving we get m = 1/200 and b = 1/1200
so required ratio = (1/200) : (1/1200) = 6:1
Hence, the ratio of daily work done by a man to that boy is 6:1.
10. Rani mixes 70kg of sugar worth Rs.28.50 per kg with 100kg of sugar worth Rs.30.50 per kg. At what rate shall he sell the mixture to gain 10 %?
A. Rs.29.75
B. Rs.32.64
C. Rs.31.50
D. Rs.30.46
Answer – B. Rs.32.64
Explanation:
70/100 = 100x – 30.50(110)/28.50(110)-100x
0.7 = 100x-3355/3135-100x
2194.5 – 70x = 100x-3355
170x = 5549.5
X = 32.64
